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Question

Concave mirror of radius of curvature 20 cm has object placed 15 cm from its pole on the principle axis. Which of the following correctly determine the position of the image, magnification and nature of image.

A
30 cm, +2, virtual
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B
30 cm, 2, Real
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C
+15 cm, 2, Real
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D
30 cm, +2, Real
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Solution

The correct option is B 30 cm, 2, Real
Given,

Radius of curvature, R=20 cm

Object distance, u = 15 cm

focal length, f=R2=10 cm


Using mirror formula:
1v+1u=1f

1v=110115

v=30 cm

So, the image formed is at distance 30 cm left of the pole.
As v is negative, so the image formed is real and formed in front of the mirror.

We know that the magnification formula is,

m=vu

m=(30)15

m=2 So, the image formed is also magnified and inverted.

Hence, option (b) is the correct answer.
Why this Question:
To understand the concept of mirror formula and image formation by spherical mirrors.

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