Concentrated aqueous sulphuric acid is 98% H2SO4 (w/v) and has a density of 1.80 gmL–1. Molarity of solution (1)1 M (2)1.8 M (3)10 M (4)1.5 M

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Solution

Molarity is the number of moles of solute present in 1 Liter of its solution.

$D e n s i t y o f H_{2} S O_{4} s o l u t i o n = \frac{M a s s o f s o l u t i o n}{V o l u m e o f s o l u t i o n}$
98 % of $H_{2} S O_{4}$ means 98g of $H_{2} S O_{4}$ is present in 100 ml of its solution.

$N u m b e r o f m o l e s o f H_{2} S O_{4} = \frac{W e i g h t o f H_{2} S O_{4}}{M o l e c u l a r m a s s o f H_{2} S O_{4}}$
$N u m b e r o f m o l e s o f H_{2} S O_{4} = \frac{98}{98} = 1$

$M o l a r i t y = \frac{N u m b e r o f m o l e s o f s o l u t e}{V o l u m e o f s o l u t i o n i n l i t e r s}$
$M o l a r i t y = \frac{1}{100} \times 1000 = 10 M$
So, the correct option is C.

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