Concentrated $H_{2} S O_{4}$ cannot be used to prepare HBr or HI from KBr or KI because it

reacts too slowly with KBr or KI

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reduces HBr or HI

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oxidises KBr or KI

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oxidises KBr to

{K B r O}_{3}

or KI to

K I O_{3}

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Solution

The correct option is C oxidises KBr or KI
$H_{2} S O_{4}$ when concentrated act as oxidising agent and oxidises $K B r$ and $K I$ to $B r_{2}, I_{2}$ .

Suggest Corrections

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3 N a_{2} H A s O_{3} + K B r O_{3} + 6 H C l \to 6 N a C l + K B r + 3 H_{3} A s O_{4}

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