Concentrated nitric acid, upon long standing, turns yellow-brown due to the formation of:

N O

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N O_{2}

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N_{2} O

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N_{2} O_{4}

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Solution

The correct option is B $N O_{2}$
Conc. $H N O_{3} \to$ decomposes partly on long standing in light as follows:
$2 H N O_{3} \to H_{2} O + 2 N O_{2} + \frac{1}{2} O_{2}$
This $N O_{2}$ gets dissolved in remaining $H N O_{3}$ and turns its color yellow-brown which is due to unpared electrons in $N O_{2}$

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Similar questions

Statement: Concentrated nitric acid, upon long-standing, turns yellow-brown due to the formation of $N O_{2}$ .

State whether the given statement is true or false.

H N O_{3},

H N O_{3},

H N O_{3},

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