Concentration of CN -1 in 0-1 M HCN is - Ka -4 - 10-10-A- 2-5 - 10-6 MB- 4-5 - 10-6 MC- 6-3 - 10-6 MD- 9-2 - 10-6 M

The correct option is C Concentration of CN^ 1√(K_a.C)=√(4 × 10^ 10× 0.1)=6.3× 10^ 6M ...

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Dissolution of Solids and Gases in Liquid

Concentration...

Question

Concentration of $C N^{- 1}$ in 0.1 M HCN is [Ka = 4 $\times 10^{- 10}$ ]

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5 \times 10^{- 4} m/s

= \frac{18 \times 10^{- 5}}{5} {N.s/m}^{2}, g = 10 {m/s}^{2}

= 900 {kg/m}^{3}

10^{- 4} m^{2}

2.5 \times 10^{10} \frac{N}{m^{2}}, 4 \times 10^{10} \frac{N}{m^{2}}

1 \times 10^{10} \frac{N}{m^{2}}

(H C O O^{-})

(H C O O H)

(K_{a} = 1.6 \times 10^{- 4})

5 \times 10^{- 4} m/s

= 3.6 \times 10^{- 5} {N-s/m}^{2}, g = 10 {m/s}^{2}

ρ_{o} = 900 {kg/m}^{3})

Simplify the expression 6m +10 - 10m.

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