Question

Concentration of $H^{+}$ and $O{H}^{-}$ ion in ${10}^{-8}M$ NaOH, is respectively-

• A. $1\times {10}^{-6},1\times {10}^{-8}$
• B. $0.95\times {10}^{-6},1.05\times {10}^{-8}$
• C. $0.95\times {10}^{-7},1.05\times {10}^{-7}$
• D. $1.05\times {10}^{-7},0.95\times {10}^{-7}$

Answer 1

The correct option is A $1\times {10}^{-6},1\times {10}^{-8}$

For a strong base or a strong acid, the concentration itself can be used to determined concentration of $o{n}^{-}$ and $H^{+}$ ions.

${10}^{-8}NNaOH$

$\left[O{H}^{⊝}\right]={10}^{-8}M$

$\left[H^{⊝}\right]=\frac{{10}^{-14}}{\left[o{n}^{-}\right]}M[\because [H^{+}\left]\right[o{n}^{[}-\left]\right]={10}^{-14}]$

$\left[H^{+}\right]={10}^{-6}M$.