Question

Condition for maximum yield of $C_2{H}_{5}Cl$ is-

• A. $C_2{H}_6\left(excess\right)+C{l}_2\stackrel{U.V.Light}{\to }$
• B. $C_2{H}_6+C{l}_2\underset{Roomtemp.}{\stackrel{Dark}{}}$
• C. $C_2{H}_6+C{l}_2\left(excess\right)\stackrel{U.V.Light}{\to }$
• D. $C_2{H}_6+C{l}_2\stackrel{U.V.Light}{\to }$

Answer 1

The correct option is A $C_2{H}_6\left(excess\right)+C{l}_2\stackrel{U.V.Light}{\to }$

The optimum reaction must have excess alkane to prevent multiple substitution . This is an example of free radical chlorination, in which sunlight is a prerequisite.

a) $C_2{H}_6\left(excess\right)+C{l}_2\stackrel{U.V.Light}{\to }\underset{Ethylchloride\left(Majorproduct\right)}{C_2{H}_{5}Cl}+HCl$