Condition satisfied by 2x +3y = -5 and 4x +6y -10 = 0 is

a₁/a₂ ≠ b₁/b₂ = c₁/c₂

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a₁/a₂ = b₁/b₂ = c₁/c₂

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a₁/a₂ = b₁/b₂ ≠ c₁/c₂

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a₁/a₂ ≠ b₁/b₂

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Solution

The correct option is C
a₁/a₂ = b₁/b₂ ≠ c₁/c₂

$a_{1}$ = 2 $b_{1}$ = 3 $c_{1}$ = 5

$a_{2}$ = 4 $b_{2}$ = 6 $c_{2}$ = -10

$\frac{a_{1}}{a_{2}}$ = $\frac{2}{4}$ = $\frac{1}{2}$ ,

$\frac{b_{1}}{b_{2}}$ = $\frac{3}{6}$ = $\frac{1}{2}$ ,

$\frac{c_{1}}{c_{2}}$ = $\frac{5}{- 10}$ = - $\frac{1}{2}$

$\frac{a_{1}}{a_{2}}$ = $\frac{b_{1}}{b_{2}}$ ≠ $\frac{c_{1}}{c_{2}}$ .

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Similar questions

Condition satisfied by the pair of equation $2 x + 3 y = - 5$ and $4 x + 6 y - 10 = 0$ is

2 x - 3 y + 5 = 0

6 y - 4 x + 10 = 0

2 x - 3 y + 5 = 0

6 y - 4 x = 10

2 x + 3 y = 5

4 x + 6 y = 10

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