Conductance is directly proportional to area of the vessel and the concentration of solution in it and is inversely proportional to the length of the vessel, then the unit of the constant of proportionality is:

S m m o l^{- 1}

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S m^{2} m o l^{- 1}

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S^{- 2} m_{2} m o l

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S^{2} m^{2} m o l^{- 2}

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Solution

The correct option is A $S m m o l^{- 1}$
$given conductance \propto \frac{Area . concentration}{length} ⟹ conductance \propto \frac{m^{2} . m o l L^{- 1}}{M}$
$S . m^{- 1} ⟹ s .7 unit of conductivity$
$S . m^{- 1} ⟹ \frac{K . m^{2} m o l L^{- 1}}{m}$
$K = S . m^{- 2} m o l^{- 1} L (m^{3}) = S . m m o l^{- 1}$

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Conductance is directly proportional to area of the vessel and the concentration of solution in it and is inversely proportional to the length of the vessel, then the unit of the constant of proportionality is:

The correct option is A Smmol−1given conductance∝Area .concentrationlength⟹conductance∝m2 . mol L−1MS.m−1⟹s.7 unit of conductivityS.m−1⟹K.m2 mol L−1mK=S.m−2mol−1L(m3)=S.m mol−1