CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Conduction of nerve impulse is a wave of followed by .

A
depolarisation
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
repolarisation
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
hyperpolarisation
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
polarisation
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B repolarisation
In the normal resting condition, the outer side of the nerve fibre carries positive charge. This is called polarised state. This polarisation is due to more Na+ions outside the axon membrane. On stimulation the axon membrane at a spot becomes more permeable to Na+ which moves inwards and causes loss of polarisation (depolarised). This depolarisation becomes a stimulus for the next neighbouring area of the membrane which in turn becomes depolarised. Meanwhile, the previous area becomes repolarised due to the active transport of Na+ions again to the outside. So the conduction of a nerve impulse or action potential is a wave of depolarisation followed by repolarisation.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Functions of a Neuron
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon