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Question

Conduction of nerve impulse is a wave of followed by .

A
depolarisation
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B
repolarisation
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C
hyperpolarisation
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D
polarisation
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Solution

The correct option is B repolarisation
In the normal resting condition, the outer side of the nerve fibre carries positive charge. This is called polarised state. This polarisation is due to more Na+ions outside the axon membrane. On stimulation the axon membrane at a spot becomes more permeable to Na+ which moves inwards and causes loss of polarisation (depolarised). This depolarisation becomes a stimulus for the next neighbouring area of the membrane which in turn becomes depolarised. Meanwhile, the previous area becomes repolarised due to the active transport of Na+ions again to the outside. So the conduction of a nerve impulse or action potential is a wave of depolarisation followed by repolarisation.

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