Question

Conductivity of $0.12MCuS{O}_4$ Solution at 298 k is $1.8\times {10}^{-2}Sc{m}^{-1}.$ Calculate its equivalent conductivity.

Answer 1

Given:-

Concentration of $CuS{O}_4⟶0.12M$

Conductivity $K=1.8\times {10}^{-2}Sc{m}^{-1}$

Equivalent conductivity= ${\wedge }_{eq}=\frac{K}{N}\times 1000$

$N⟶$ Normality

Normality= n $\times$ Molarity

$\Rightarrow n=2$ for $CuS{O}_4$

$N=2\times 0.12$

$=0.24N$

${\wedge }_{eq}=\frac{1.8\times {10}^{-2}}{0.24}\times 100$

${\wedge }_{eq}=7.5Sc{m}^{-1}equi{v}^{-1}$