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Question

Conductivity of a saturated solution of a sparingly soluble salt AB at 298K is 1.85×105Sm1. Solubility product of the salt AB at 298K is :


[Given Λom(AB)=140×104Sm2mol1]

A
1.32×1012
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B
1.74×1012
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C
5.7×1012
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D
7.5×1012
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Solution

The correct option is B 1.74×1012
Λ0m=k×1000C

140×104=1.85×105×11000C as units are in metres

C1.32×106

ABA++B

Ksp=C2=1.74×1012

Hence, option B is correct.

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