Conductivity of saturated solution of silver phosphate is 9 - 10-6 S m -1 and equivalent conductivity 1-5 - 10-4 S m 2 -equivalent- Find K sp of Ag 3 P O 4A- 3-49 - 108 molL -14B- 3-49 - 10-8 molL -14- 6-98 - 108 molL -14D- 6-98 - 10-8 molL -14

The correct option is A 3.49 × 10^8(mol L^ 1)^4Given conductivity of Ag_3PO_4, k=9 × 10^ 6 S m^ 1 eq of saturated solution Conductivity of Ag_3PO_4 at infinit ...

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Standard XII

Chemistry

Conductance of Electrolytic Solution

Conductivity ...

Question

Conductivity of saturated solution of silver phosphate is $9 \times 10^{- 6}$ $S m^{- 1}$ and equivalent conductivity $1.5 \times 10^{- 4}$ $S m^{2}$ /equivalent. Find $K_{s p}$ of $A g_{3} P O_{4}$ .

3.49 \times 10^{8} (m o l L^{- 1})^{4}

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3.49 \times 10^{- 8} (m o l L^{- 1})^{4}

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6.98 \times 10^{8} (m o l L^{- 1})^{4}

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6.98 \times 10^{- 8} (m o l L^{- 1})^{4}

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Solution

The correct option is A $3.49 \times 10^{8} (m o l L^{- 1})^{4}$
Given conductivity of $A g_{3} P O_{4}$ , $k = 9 \times 10^{- 6} S m^{- 1} e q$ of saturated solution
Conductivity of $A g_{3} P O_{4}$ at infinite dilution,
$λ^{o} = 1.5 \times 10^{- 4} S m^{2} e q$
Thus, as concentration, $C = \frac{c o n d u c t i v i t y}{λ^{o}}, k$
$\Rightarrow C = \frac{9 \times 10^{- 6} S m^{- 1} e q}{1.5 \times 10^{- 4} S m^{2} e q} = 0.06 m^{- 3} m o l$
$\Rightarrow C = 0.06 \times 10^{3} d m^{- 3} m o l$
$A g_{3} P O_{4} ⇌ 3 A g^{+} + P O_{4}^{3 -}$
$\Rightarrow K_{s p} = [A g^{+}]^{3} [P O_{4}]^{3 -}$
$\Rightarrow K_{s p} = (3 C)^{3} (C) = 27 C^{4}$
$= 27 \times [0.06 \times 10^{3}]^{4}$
$\Rightarrow K_{s p} = 3.49 \times 10^{8} (m o l L^{- 1})^{4}$

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Conductivity of saturated solution of silver phosphate is 9×10−6 S m−1 and equivalent conductivity 1.5 ×10−4 S m2/equivalent. Find Ksp of Ag3PO4.

Conductivity of saturated solution of silver phosphate is $9 \times 10^{- 6}$ $S m^{- 1}$ and equivalent conductivity $1.5 \times 10^{- 4}$ $S m^{2}$ /equivalent. Find $K_{s p}$ of $A g_{3} P O_{4}$ .