Conjugate base of $H_{2} P O_{4}^{-}$ is

H P O_{4}^{2 -}

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P O_{4}^{3 -}

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H_{3} P O_{4}

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H P O_{4}^{-}

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Solution

The correct option is A $H P O_{4}^{2 -}$
According to the Bronsted lowry theory of acids and bases: A conjugate acid is formed when a proton is added to a base, and a conjugate base is formed when a proton is removed from an acid.
$A c i d - H^{+} = conjugate base$
$H_{2} P O_{4}^{-} - H^{+} = H P O_{4}^{2 -}$

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