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Byju's Answer
Standard XII
Chemistry
Oxyacids of Phosphorus
Conjugate bas...
Question
Conjugate base of
H
2
P
O
−
4
is:
A
H
3
P
O
4
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B
P
2
O
5
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C
P
O
3
−
4
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D
H
P
O
2
−
4
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Solution
The correct option is
D
H
P
O
2
−
4
H
2
P
O
−
4
a
c
i
d
+
H
2
O
→
H
3
O
+
+
H
P
O
2
−
4
conjugated base
H
2
P
O
−
4
gives
H
P
O
2
−
4
(conjugated base) in aqueous solutions. It acts as proton donor.
Note: An acid and its conjugate base differ by one proton only. An acid loses one proton to form a conjugate base.
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Similar questions
Q.
Equivalent weight of
H
3
P
O
4
in each of the reaction will be respectively:
H
3
P
O
4
+
O
H
−
→
H
2
P
O
−
4
+
H
2
O
H
3
P
O
4
+
2
O
H
−
→
H
P
O
2
−
4
+
2
H
2
O
H
3
P
O
4
+
3
O
H
−
→
P
O
3
−
4
+
3
H
2
O
Q.
Three reactions involving
H
2
P
O
−
4
are given?
(i)
H
2
P
O
4
+
H
2
O
→
H
3
O
+
+
H
2
P
O
−
4
(ii)
H
2
P
O
−
4
+
H
2
O
→
H
P
O
2
−
4
+
H
3
O
+
(iii)
H
2
P
O
−
4
+
O
H
−
→
H
3
P
O
4
+
O
2
−
In which of the given does
H
2
P
O
−
4
act as n acid?
Q.
Calculate the pH of
0.1
M solution of (i)
N
a
H
C
O
3
, (ii)
N
a
2
H
P
O
4
and (iii)
N
a
H
2
P
O
4
.
Given that:
C
O
2
+
H
2
O
⇌
H
+
+
C
O
2
−
3
;
K
1
=
4.2
×
10
−
7
M
H
C
O
−
3
⇌
H
+
+
C
O
2
−
3
;
K
2
=
4.8
×
10
−
11
M
H
2
P
O
4
⇌
H
+
+
H
2
P
O
−
4
;
K
1
=
7.5
×
10
−
3
M
H
2
P
O
−
4
⇌
H
+
+
H
P
O
2
−
4
;
K
2
=
6.2
×
10
−
8
M
H
P
O
2
−
4
⇌
H
+
+
P
O
3
−
4
;
K
3
=
1.0
×
10
−
12
M.
Q.
Three reactions involving
H
2
P
O
−
4
are given below.
I.
H
3
P
O
4
+
H
2
O
→
H
3
O
+
+
H
2
P
O
−
4
II.
H
2
P
O
−
4
+
H
2
O
→
H
P
O
2
−
4
+
H
3
O
+
III.
H
2
P
O
−
4
+
O
H
−
→
H
3
P
O
4
+
O
2
−
In which of the above does
H
2
P
O
−
4
act as an acid?
Q.
The hydrolysis constant
K
H
for the reaction
H
2
P
O
−
4
+
H
2
O
→
H
3
P
O
4
+
O
H
−
is
1.4
×
10
−
12
. The ionisation constant for
H
3
P
O
4
+
H
2
O
→
H
2
P
O
−
4
+
H
3
O
+
is:
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