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Arrhenius Acid

Conjugate bas...

Question

Conjugate base of $H S O_{4}^{-}$ is:

H_{2} S O_{4}

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S O_{4}^{2 -}

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S O_{4}^{-}

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H_{2} S O_{4}^{-}

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Solution

The correct option is B $S O_{4}^{2 -}$
Conjugate base of $H S O_{4}^{-}$ is $S O_{4}^{2 -}$

Note: An acid and its conjugate base differ by one proton only.

$H S O_{4}^{-} + H_{2} O \to S O_{4}^{2 -} + H_{3} O^{+}$

Option B is correct.

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Similar questions

Conjugate base of the following reaction is

Reaction:H2SO4 + H2O (reversibly giving)H3O^+ + HSO4^-

Ans gn:H3O^+ ,H2SO4

H_{2} S O_{4}

H_{2} S O_{4} + H_{2} O \to H_{3} O^{+} + H S O_{4}^{-}

H_{2} S O_{4}

H_{2} S O_{4} ⟶ H^{+} + H S O_{4}^{-}

100 %

H_{2} S O_{4}^{-} ⟶ H^{+} + S O_{4}^{2 -}

10 %

0.2 M

H_{2} S O_{4}

[H S O_{4}^{-}]

H_{2} S O_{4} ⟶ H^{+} + H S O_{4}^{-}

H S O_{4}^{-} ⟶ H^{+} + S O_{4}^{2 -}

0.2 M

H_{2} S O_{4}

[S O_{4}^{2 -}]

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