Conjugate base of $H S O_{4}^{-}$ is:

S O_{4}^{2 -}

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H_{2} S O_{4}

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H_{3} S O_{4}^{+}

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None of these

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Solution

The correct option is B $S O_{4}^{2 -}$
Conjugate acid base differ by H
Acid - $H^{+} ⟶$ Conjugate base
$H S O_{4}^{-} - H^{+} ⟶ S O_{4}^{2 -}$

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Similar questions

H^{+}, H S O_{4}^{-}, S O_{4}^{2 -}

H_{2} S O_{4}

0.20

H_{2} S O_{4} \to H^{+} + H S O_{4}^{-}

H S O_{4}^{-} ⇌ S O_{4}^{2 -}; K_{2} = 10^{- 2}

H_{2} S O_{4}

Conjugate base of the following reaction is

Reaction:H2SO4 + H2O (reversibly giving)H3O^+ + HSO4^-

Ans gn:H3O^+ ,H2SO4

The species: H₂O,, and NH₃ can act both as Brönsted acids and bases. For each case give the corresponding conjugate acid and base.

H S O_{4}^{-}

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