Conjugate base of $N H_{3}$ is:

N H_{4}^{+}

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N H_{2}^{+}

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N H_{2}^{-}

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N_{2}

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Solution

The correct option is D $N H_{2}^{-}$
$N H_{3}$ can donate a proton & act as an acid.
$∴ N H_{3} - H^{+} \to N H_{2}^{-}$
$∴ N H_{2}^{-}$ is the conjugate base of $N H_{3}$

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