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Question

Conjugate of the hyperbola, x2a2−y2b2=1 is .

A
x2a2+yb2=1
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B
x2a2-y2b2=1
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C
x2a2-y2b2=-1
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D
-x2a2-y2b2=1
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Solution

The correct option is C x2a2-y2b2=-1
We say hyperbola A is the conjugate hyperbola of the hyperbola B, if the transverse axis of A is the conjugate axis of the hyperbola B and vice versa. For the standard hyperbola x2a2y2b2=1, the equation of conjugate hyperbola is given by x2a2y2b2=1

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