Conjugate surds of $a + \sqrt{b}$ ?

$a - \sqrt{b}$

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$b + \sqrt{a}$

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$b - \sqrt{a}$

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$\sqrt{a} - b$

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Solution

The correct option is A
$a - \sqrt{b}$

Two terms of two Quadratic surds joined by alternate signs are called conjugate surds.

Example

Conjugate surd of $2 + \sqrt{3}$ is $2 - \sqrt{3}$

Suggest Corrections

Similar questions

Establish the following vector inequalities geometrically or otherwise:

(a) |a + b| ≤ |a| + |b|

(b) |a + b| ≥ ||a| − |b||

(d) |a − b| ≥ ||a| − |b||

When does the equality sign above apply?

a = i - j + k, a \cdot b = 0, a \times b = c,

c = - 2 i - j + k

b

Given a + b + c + d = 0, which of the following statements are correct:

(a) a, b, c, and d must each be a null vector,

(b) The magnitude of (a + c) equals the magnitude of (b + d),

(d) b + c must lie in the plane of a and d if a and d are not collinear, and in the line of a and d, if they are collinear?

Show that a. (b × c) is equal in magnitude to the volume of the parallelepiped formed on the three vectors, a, b and c.

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