Consider a 3 x 3 real symmetric matrix S such that two of its eigen values are a≠0,b≠0 with respective eigen vectors ⎡⎢⎣x1x2x3⎤⎥⎦,⎡⎢⎣y1y2y3⎤⎥⎦. If a≠b then x1y1+x2y2+x3y3 equals
A
a
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B
b
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C
ab
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D
0
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Solution
The correct option is D 0 The eigen vectors of a real symmetric matrix corresponding to distinct eigen values are othogonal.
so, X.Y=0⇒⎡⎢⎣x1x2x3⎤⎥⎦⎡⎢⎣y1y2y3⎤⎥⎦=x1y1+x2y2+x3y3=0