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Question

Consider a 65 kg ice skater is being pushed by two other with forces F1=26.4 N and F2=18.6 N as shown in the figure. If the coefficient of static friction is 0.04 and coefficient of kinetic friction is 0.02, which of the following option(s) is/are correct?
(Take g=10 m/s2)

A
Net force acting on the skater is 32.3 N.
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B
Acceleration of the skater is 0.23 m/s2.
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C
Kinetic friction experienced by skater is 26 N.
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D
Kinetic friction experienced by skater is 13 N.
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Solution

The correct option is D Kinetic friction experienced by skater is 13 N.
Net force acting on the skater,
Fnet=F21+F22=(26.4)2+(18.6)2=32.3 N
Reaction on skater, N=mg=65×10=650 N
Static friction, fs=μsN=0.04×650=23 N
Since Fnet>fs, Therefore skater slides along the direction of resultant.
Kinetic friction, fk=μkN=0.02×650=13 N
Acceleration of the skater, a=Fnetfkm=32.31362=0.23 m/s2

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