Consider a beam of electrons moving perpendicular to a uniform magnetic field of 10 Tesla as shown in the figure. The beam carries a current of 10−5 amp. The force on 1 m length of beam is :
A
10−5N
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B
10−6N
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C
10−3N
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D
10−4N
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Solution
The correct option is D10−4N F=ilB since both l and B are perpendicular to each other. ∴F=10−5×1×10N=10−4N