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Question

Consider a block size 512 bytes, search key field 9 bytes long, block pointer size is 6 byte and record pointer is 7 byte long. if a level 3 B+ tree is constructed considering root as level 0, find the maximum number of entries in the B+ tree ?

A
(34)3(31)2 entries
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B
(34)231 entries
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C
(34)331 entries
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D
(31)334 entries
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Solution

The correct option is C (34)331 entries
option (a)

Order of internal node is
n*6 + (n-1) * 9512
6n+9n - 9 512
15n 521
n 34

Order of leaf node is
n* (9+7) +6512
16n 506
n 31

maximum number of entries in level 3 B + tree is

= (34)331

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