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Byju's Answer

Standard XII

Physics

Capacitance of a Random Conductor

Consider a ca...

Question

Consider a capacitor-charging circuit. Let $Q_{1}$ be the charge given to the capacitor in a time interval of $10 m s$ and $Q_{2}$ be the charge given in the next time interval of $10 m s$ . Let $10 μ C$ charge be deposited in a time interval $t_{1}$ and the next $10 μ C$ charge is deposited in the next time interval $t_{2}$ .

Q_{1} > Q_{2}, t_{1} > t_{2}

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Q_{1} > Q_{2}, t_{1} < t_{2}

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Q_{1} < Q_{2}, t_{1} > t_{2}

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Q_{1} < Q_{2}, t_{1} < t_{2}

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Solution

The correct option is D $Q_{1} > Q_{2}, t_{1} < t_{2}$
Both the rates of charging and discharging of capacitors decrease with time.
Hence when charging, the charge deposited in first 10ms $Q_{1}$ is greater than $Q_{2}$ in next 10 ms.
Similarly, with higher rate of charging in the beginning, $10 μ C$ takes lesser time to be deposited than later.

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Similar questions

Q. Consider a capacitor-charging circuit. Let Q₁ be the charge given to the capacitor in a time interval of 10 ms and Q₂ be the charge given in the next time interval of 10 ms. Let 10 μC charge be deposited in time interval t₁ and another 10 μC charge be deposited in the next time interval t₂.
(a) Q₁ > Q₂, t₁ > t₂
(b) Q₁ > Q₂, t₁ < t₂
(c) Q₁ < Q₂, t₁ > t₂
(d) Q₁ < Q₂, t₁ < t₂

Q. In a capacitor charging unit, let

Q_{1}

be the charge given to the capacitor in a time interval

Δ t

and

Q_{2}

be the charge given in the next equal time inertial

Δ t

. In the same unit, let charge

Δ q

be deposited in a time interval

t_{1}

and the next equal charge

Δ q

be deposited in a time interval

t_{2}

, then.

A heat engine absorbs heat $Q_{1}$ at temperature $T_{1}$ and heat $Q_{2}$ at temperature $T_{2}$ . Work done by the engine is $(Q_{1} + Q_{2}) J$ . This data:

Q. Point charges

q_{1}

and

q_{2}

are placed in air at a distance 'r'. The ratio of the force on charge

q_{1}

by charge

q_{2}

and force on charge

q_{2}

by charge

q_{1}

is?

Q. The given RC circuit has two switches

S_{1}

and

S_{2}

. The switch

S_{2}

is closed till the capacitor

C

attains its maximum possible charge

q_{0}

. Then,

S_{2}

is opened and

S_{1}

is closed simultaneously till the capacitor releases half of its total stored charge

q_{0}

for a time interval

t_{1}

. Finally

S_{1}

is opened and

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is closed till the capacitor attains a charge

(3 / 4) q_{0}

for a time interval

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(t_{1} / t_{2})

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Consider a capacitor-charging circuit. Let Q1 be the charge given to the capacitor in a time interval of 10ms and Q2 be the charge given in the next time interval of 10ms. Let 10μC charge be deposited in a time interval t1 and the next 10μC charge is deposited in the next time interval t2.