Consider a charged particle of mass m and charge q released from the origin in a region of magnetic field, →B=B0^j and electric field →E=E0^k . The speed of the particle as a function of its z−coordinate will be (Neglect gravity)
A
2√qE0zm
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B
√3qE0zm
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C
√2qE0zm
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D
√qE0zm
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Solution
The correct option is C√2qE0zm The speed changes only due to electric field and hence work done is only due to the electric field. Applying kinetic energy - work theorem we get, △K=Wnet⇒Kf−Ki=Welec⇒12mv2−0=qE0z⇒V=√2qE0zm