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Question

Consider a circle with its centre lying on the focus of the parabola y2=2px such that it touches the directrix of the parabola. Then the point of intersection of the circle and parabola can be

A
(p2,p)
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B
(p2,p)
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C
(p2,p)
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D
(p2,p2)
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Solution

The correct options are
B (p2,p)
C (p2,p)
The focus of the parabola y2=2px is (p2,0) and directrix is x=p2.
Centre of circle is (p2,0)
and radius =p2+p2=p
Equation of circle is (xp2)2+y2=p2
Solving with y2=2px, we get
(xp2)2+2pxp2=0
4x2+8px4px3p2=0
4x2+4px3p2=0
4x2+6px2px3p2=0
(2xp)(2x+3p)=0
x=p2 or 3p2

For x=p2,
y2=2p×p2
y=±p

For x=3p2,
y2=2p×3p2=6p2 (not possible)
Required points are (p2,±p)

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