Consider a compound slab consisting of two different materials having equal lengths, thicknesses and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is
A
√2K
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B
3K
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C
43K
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D
23K
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Solution
The correct option is A43K The thermal resistances can be added as they are in series. But, note that the width of the combined slab is twice the width of individual slab.