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Question

Consider a family of circles which are passing through M(1,1) and are tangent to x-axis. If (h,k) is the centre of circle, then

A
k12
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B
12k12
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C
k12
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D
0<k<12
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Solution

The correct option is A k12

Equation of circle with centre (h,k) and to using x-axis is given by

(xh)2+(yk)2=k2

x2+h2(2h)x+y2+k2(2k)y=k2

x2+y2(2h)x(2k)y+h2=0

It passes through the point (1,1)

12+122h2k+h2=0

h22h+(22k)=0

As value of h is real, D0

(2)24(22k)0

k12.


802872_762863_ans_61a80f82680642ff8a0ccb92c34e45b9.png

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