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Question

Consider a gaseous reaction A(g)+B(g)3C(g), the rate of the reaction is given by r=k[A][B]2. If the volume of the reaction vessel containing these gases is suddenly reduced to 14th of the initial volume, then the rate of the reaction relative to the original rate would be:

A
64 times
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B
16 times
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C
643 times
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D
6427 times
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Solution

The correct option is A 64 times
On reducing the volume to 14th, the concentration quadruples.
So, r(new)r=k(4[A])(4[B])2k[A][B]2
=64k[A][B]2k[A][B]2=64

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