Question

Consider a gaseous reaction, the rate of which is given by $k\left[A\right]\left[B\right]$. The volume of the reaction vessel containing these gases is suddenly reduced to $1/4^{th}$ of the initial volume. The rate of the reaction as compared with original rate is:

• A. $\frac{1}{16}times$
• B. $16times$
• C. $\frac{1}{8}times$
• D. $8times$

Answer 1

Answer: (B)

$16times$

$r_1=k\left[A\right]\left[B\right]$

$(V=\frac{1}{4},soconcentration\uparrow 4times)$

$\therefore r_2=k\left[4A\right]\left[4B\right]$

$r_2=16r_1$
Option B is correct.