Consider a gravity-free hall in which an experimenter of mass 50 kg is resting on a 5 kg pillow, 8 ft above the floor of the hall. He pushes the pillow down so that it starts falling at a speed of 8 ft/s. The pillow makes a perfectly elastic collision with the floor, rebounds and reaches the experimenter's head. Find the time elapsed in the process.
2.22 s
The situation shown is depicted in following figure.
Let the velocity of man be v(wrt ground) upwards. As the momentum is conserved,
5 × 8 = 50 × v
v = 0.8 ft/s
Pillow takes 1s to reach the wall.
As the collision of pillow with the wall is elastic, pillow comes back towards P with 8 ft/s.
Now it again takes 1s to reach P from the wall.
Total time consumed = 2s
But in these 2s the man would have moved (2 × 0.8) ft upwards.
Let time taken by pillow to reach the man from A be t.
So v distance covered by man = 0.8 t further.
And distance that pillow has to cover = (1.6 + 0.8t)
As the pillow is hitting the man, both should have covered the same distance
Therefore, 8t = 1.6 + 0.8t ⇒ t = 0.22s
∴ Total time consumed = 2 + 0.22 = 2.22s