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Standard XII

Physics

Nuclear Fusion

Consider a nu...

Question

Consider a nuclear reaction $A + B \to C$ . A nucleus A moving with kinetic energy of 5 MeV collides with a nucleus B moving with kinetic energy of 3 MeV and forms a nucleus C in the exited state with excitation energy 10 MeV. The kinetic energy of nucleus C just after its formation is $\frac{5.3}{p} M e V$ . Take masses of nuclei of A, B and C as 25 amu, 10 amu and 34.995 amu, respectively and 1 amu $= 930 M e V / c^{2} .$ Find value of p___.

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Solution

$M_{A} C^{2} + K_{A} + M_{B} C^{2} + K_{B} = M_{C} C^{2} + K_{C} + e x c i t e d e n e r g y K_{C} = 2.65 M e v$

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Similar questions

Q. Consider the nuclear reaction

A + B \to C

, and nuclei

A

and

B

are moving with kinetic energies of 5

M e V

and 3

M e V

respectively to form a nucleus

C

, which is in its excited state with excitation energy 10

M e V

. If the

K . E

C

just after formation is

x M e V

, then the value of

x

is
[Answer upto two decimal points]
[Take mass of nuclei

A

B

and

C

are 25

D a

, 10

D a

and 34.995

D a

respectively and

1 D a = \frac{930 M e V}{c^{2}}

]

Q. A free nucleus of mass

24 a m u

, intially at rest emits a gamma photon. The energy of the photon is

7 M e V

. The kinetic energy of recoiling nucleus is approximately equal to [Take;

1 a m u = 9.31 M e V

]

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Initially the nucleus of radium – 226 is at rest. It decays due to which and a particle and the nucleus of radon are created. The released energy during the decay is 4.87 Mev, which appears as the kinetic energy of the two resulted particles. $[m_{α} = 4.002 a m u, m_{R n} = 222.017 a m u]$

Kinetic energies of particle & radon nucleus are respectively

Q. A nucleus at rest undergoes

α - d e c a y

emitting an

α - p a r t i c l e

of de Broglie wavelength

λ = 5.76 \times 10^{- 15}

m. If the mass of the daughter nucleus is 223.610 amu and that of the

α - p a r t i c l e

is 4.002 amu, determine the total kinetic energy in the final state, Hence, obtain the mass of parent nucleus in amu.

(1 a m u = 931.470 M e V c^{- 2})

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MAC2+KA+MBC2+KB=MCC2+KC+excitedenergyKC=2.65Mev

$M_{A} C^{2} + K_{A} + M_{B} C^{2} + K_{B} = M_{C} C^{2} + K_{C} + e x c i t e d e n e r g y K_{C} = 2.65 M e v$