The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Initially the nucleus of radium – 226 is at rest. It decays due to which and a particle and the nucleus of radon are created. The released energy during the decay is 4.87 Mev, which appears as the kinetic energy of the two resulted particles. $[m_{α} = 4.002 a m u, m_{R n} = 222.017 a m u]$

Kinetic energies of particle & radon nucleus are respectively

Q. A nucleus at rest undergoes

α - d e c a y

emitting an

α - p a r t i c l e

of de Broglie wavelength

λ = 5.76 \times 10^{- 15}

m. If the mass of the daughter nucleus is 223.610 amu and that of the

α - p a r t i c l e

is 4.002 amu, determine the total kinetic energy in the final state, Hence, obtain the mass of parent nucleus in amu.

(1 a m u = 931.470 M e V c^{- 2})

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MAC2+KA+MBC2+KB=MCC2+KC+excitedenergyKC=2.65Mev

$M_{A} C^{2} + K_{A} + M_{B} C^{2} + K_{B} = M_{C} C^{2} + K_{C} + e x c i t e d e n e r g y K_{C} = 2.65 M e v$