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Question

Consider a parallel beam of light of wavelength 600 nm and intensity 100 W/m2. How many photons cross 1 m2 area perpendicular to beam in one second?

A
3×1016
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B
3×1014
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C
3×109
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D
3×104
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Solution

The correct option is C 3×1016
The energy of each photon, E=hcλ

=4.14×1015×3×108×109600=2.07eV

Intensity =100W/m2

Power = Intensity × Area =100×1100×1100=0.01J

Time =1sec

Therefore,

Energy =0.01J

Number of photons =EnergyofallphotonsEnergyofonephoton=0.01J2.07×1019×1.6=3×1016

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