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Question

Consider a parallel-plate capacitor of capacitance 10 μF with air filled in the gap between the plates. Now, one half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in the figure. The capacitance of the capacitor changes to

A
25 μF
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B
20 μF
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C
20 μF
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D
40 μF
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Solution

The correct option is A 25 μF
From given we can redraw circuit as

Ceq=C1+C2=Kε0A2d+ε0A2d=Kε0A2d+ε0A2d=ε0A2d[K+1]

From given ε0A2d=10 μF and K=4.
On substituting these values
we get, Ceq=25 μF

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