Consider a particle initially moving with a velocity of $5 m s^{- 1}$ starts decelerating at a constant rate of $2 m s^{- 2}$ . Determine the time at which the particle becomes stationary.

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Solution

V=U+AT
Since v=0, we substitute values.
0=5-2t(because it is decelerating and hence it is negative).
T=2.5s
Displacement in nth second is given as
S_n=u+a(2n-1)/2

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Consider a particle initially moving with a velocity of 5ms−1 starts decelerating at a constant rate of 2ms−2. Determine the time at which the particle becomes stationary.

V=U+ATSince v=0, we substitute values.0=5-2t(because it is decelerating and hence it is negative).T=2.5sDisplacement in nth second is given asSn=u+a(2n-1)/2

Consider a particle initially moving with a velocity of $5 m s^{- 1}$ starts decelerating at a constant rate of $2 m s^{- 2}$ . Determine the time at which the particle becomes stationary.

V=U+AT
Since v=0, we substitute values.
0=5-2t(because it is decelerating and hence it is negative).
T=2.5s
Displacement in nth second is given as
S_n=u+a(2n-1)/2