Consider a particle moving in simple harmonic motion according to the equation x=2.0cos(50Π t+tan−10.75)
where x is in centimeter and t in second. The motion is started at t = 0. (a) When does the particle come to rest for the second time?
v=dxdt=−π sin(50Π t+tan−10.75)
Find t when v=0
⇒=−100π sin(50π t+tan−10.75)
First time particle will come to rest after start (i.e., t=0) is when π=1. second time it will happen when n
t=2π−0.6450π (∵ tan−10.75=0.64)