Question

Consider a pin jointed plane frame ABCD as shown in figure below:

The magnitude of force in member BD is _____ kN.

• A. 28.25

Answer 1

The correct option is A 28.25



By method of section

$\Sigma F_y=0$

$\Rightarrow F_{BD}\cos 45{}^{\circ }=20$

$\Rightarrow F_{BD}=\sqrt{2}\times 20$

$=28.28kN$