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Question

Consider a plane x+yz=1 and point A(1,2,3). A line L has the equation x=1+3r,y=2r and z=3+4r.

The distance between the points on the line which are at a distance of 43 from the plane is 


A
426   
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B
20  
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C
1013   
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D
none of these 
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Solution

The correct option is A 426   
The distance of point (1+3r,2r,3+4r) from the plane is 1+3r+2r34r11+1+1=43
|2r+1|3=43
r=32,52
Hence, the points are A(112,12,182) and B(132,92,142)
AB=416=426

Mathematics

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