Consider a point charge with q - 1-5 - 10-8 C- Then- the radius of an equipotential surface having a potential of 30 V is -

The correct option is B 4.5 m Electric potential due to a point charge =kqr 30V=k× 1.5× 10^ 8Cr r=9× 10^9 #160;× 1.5× 10^ 830m r=4.5 ...

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Standard XII

Physics

Electric Field Due to Charge Distributions - Approach

Consider a po...

Question

Consider a point charge with $q = 1.5 \times 10^{- 8} C$ . Then, the radius of an equipotential surface having a potential of $30 V$ is :

0.45 m

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4.5 m

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infinite

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none of the above

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Solution

The correct option is B $4.5 m$
Electric potential due to a point charge
$= \frac{k q}{r}$
$⟹ 30 V = \frac{k \times 1.5 \times 10^{- 8} C}{r}$
$⟹ r = \frac{9 \times 10^{9} \times 1.5 \times 10^{- 8}}{30} m$
$⟹ r = 4.5$ $m$

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Consider a point charge with q=1.5×10−8C. Then, the radius of an equipotential surface having a potential of 30V is :

The correct option is B 4.5mElectric potential due to a point charge=kqr⟹30V=k×1.5×10−8Cr⟹r=9×109×1.5×10−830m⟹r=4.5 m

Consider a point charge with $q = 1.5 \times 10^{- 8} C$ . Then, the radius of an equipotential surface having a potential of $30 V$ is :

The correct option is B $4.5 m$
Electric potential due to a point charge
$= \frac{k q}{r}$
$⟹ 30 V = \frac{k \times 1.5 \times 10^{- 8} C}{r}$
$⟹ r = \frac{9 \times 10^{9} \times 1.5 \times 10^{- 8}}{30} m$
$⟹ r = 4.5$ $m$