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Question

Consider a random process Y(t) defined as Y(t)=X(t)X(t+τ) where X(t) is stationary non-periodic process and τ is constant. If RX(τ) is the autocorrelation of random process X(t), then the variance of Y(t) will be

A
2RX(0)RX(τ)
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B
2RX(0)
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C
2[RX(0)RX(τ)]
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D
2RX(τ)
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Solution

The correct option is C 2[RX(0)RX(τ)]
Y(t)=X(t)X(t+τ) and ¯¯¯¯¯¯¯¯¯¯¯¯¯X2(t)=RX(0)
Also, we have to obtain the mean value of the random process Y(t) as
E[Y(t)]=0
σ2x=E[Y2(t)]E[Y(t)]2=E[[X(t)X(t+τ)]2]
=E[X2(t)]2E[X(t).X(t+τ)]+E[X2(t+τ)]
=RX(0)2RX(τ)+RX(0)=2RX(0)2RX(τ)
=2[RX(0)RX(τ)]

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