Consider a random process Y(t) defined as Y(t)=X(t)−X(t+τ) where X(t) is stationary non-periodic process and ′τ′ is constant. If RX(τ) is the autocorrelation of random process X(t), then the variance of Y(t) will be
A
2RX(0)−RX(τ)
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B
2RX(0)
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C
2[RX(0)−RX(τ)]
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D
2RX(τ)
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Solution
The correct option is C2[RX(0)−RX(τ)] Y(t)=X(t)−X(t+τ) and ¯¯¯¯¯¯¯¯¯¯¯¯¯X2(t)=RX(0)
Also, we have to obtain the mean value of the random process Y(t) as E[Y(t)]=0 σ2x=E[Y2(t)]−E[Y(t)]2=E[[X(t)−X(t+τ)]2] =E[X2(t)]−2E[X(t).X(t+τ)]+E[X2(t+τ)] =RX(0)−2RX(τ)+RX(0)=2RX(0)−2RX(τ) =2[RX(0)−RX(τ)]