Question

Consider a ray of light incident from air onto a slab of glass (refractive index n) of width d, at an angle $\theta$.The phase difference between the ray reflected by the top surface of the glass and the bottom surface is

• A. $\frac{4\pi d}{\lambda }{(1-\frac{1}{n^2}si{n}^2\theta )}^{1/2}+\pi$
• B. $\frac{4\pi d}{\lambda }{(1-\frac{1}{n^2}si{n}^2\theta )}^{1/2}$
• C. $\frac{4\pi d}{\lambda }{(1-\frac{1}{n^2}si{n}^2\theta )}^{1/2}+\frac{\pi }{2}$
• D. $\frac{4\pi d}{\lambda }{(1-\frac{1}{n^2}si{n}^2\theta )}^{1/2}+2\pi$

Answer 1

The correct option is A $\frac{4\pi d}{\lambda }{(1-\frac{1}{n^2}si{n}^2\theta )}^{1/2}+\pi$