Consider a reaction aG+bH→Products. When the concentration of both the reactants G and H is doubled, the rate increases by eight times. However, when a concentration of H fixed, the rate is doubled. The overall order of the reaction is:
A
0
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B
1
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C
2
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D
3
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Solution
The correct option is D 3 The rate law expression is R=k[G]a[H]b ......(1) The rate of reaction increases by a factor of 2 on doubling the concentration of 'G' . The rate law expression becomes R′2R=k2a[G]a[H]b ......(2) Divide equation (2) with equation (1) 2RR=R′=2R=k2a[G]a[H]bk[G]a[H]b Hence, 2=2a or a=1 The rate of freaction increases by a factor of 8 on doubling the concentration of 'G' and 'H' The rate law expression becomes k2a[G]a2b[H]b ......(3) Divide equation (3) with equation (1) 8RR=k2a[G]a2b[H]bk[G]a[H]b Hence, 8=2a2b or b=2 The overall order of the reaction is a+b=1+2=3