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Question

# Consider a reaction : N2+3H2⇌2NH3 Kp for the above reaction at 127∘C is 4.34×10−3 . ΔrH= −460.6 cal mol−1 . Estimate the temperature at which Kp will be 43.4×10−3

A
150 K
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B
200 K
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C
30 K
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D
80 K
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Solution

## The correct option is D 80 KVan't Hoff Equation : log(K2K1)=−ΔH∘2.303R(1T2−1T1) Given T1=127∘C=(127+273)K=400KΔH∘=−460.6 cal mol−1K1=4.34×10−3K2=43.4×10−3 Also, R=2 cal K−1 mol−1 Putting the values: log(43.4×10−34.34×10−3)=+460.62.303×2(1T2−1400) log(10)=100×(1T2−1400)1100=(1T2−1400)1T2=1100+1400=180T2=80 K

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