Question

# Consider a redox reaction : x Na2HAsO3+y NaBrO3+z HCl→NaBr+H3AsO4+NaCl where x,y,z are the stoichiometric coefficients of Na2HAsO3,NaBrO3,HCl respectively. The value of x+y+z in the above balanced redox reaction is :

A
3
B
9
C
10
D
12

Solution

## The correct option is C 10The equation before balancing is: Na2HAsO3+NaBrO3+HCl→NaBr+H3AsO4+NaCl Oxidation state As in Na2HAsO3=+3 Oxidation state As in H3AsO4=+5 Oxidation state Br in NaBrO3=+5 Oxidation state Br in NaBr=−1 Na2HAsO3 is undergoing oxidation and is the reducing agent  NaBrO3  is undergoing reduction and is the oxidising agent.. nf of Na2HAsO3=2 nf of NaBrO3=6 here 2 is common in both n-factors. ⇒Ratio of n-factors=1:3 Cross multiplying these with ratio of nf's of each other. we get, 3Na2HAsO3+NaBrO3+HCl→NaBr+H3AsO4+NaCl Balancing  As, 3Na2HAsO3+NaBrO3+HCl→NaBr+3H3AsO4+NaCl As of now oxygen already got balanced, Balancing  Na, 3Na2HAsO3+NaBrO3+6HCl→NaBr+3H3AsO4+6NaCl After this when we observe every element is balanced. so no need to follow further steps. We can also see that charge on both sides is 0. which also indicates that the equation is balanced now. 3Na2HAsO3+NaBrO3+6HCl→NaBr+3H3AsO4+6NaCl This is the final balanced equation. Comparing to the equation given in question, we get, The value of x,y,z to be 3,1,6 respectively. Value of x+y+z=3+1+6=10Chemistry

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