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Question

Consider a redox reaction :

x Na2HAsO3+y NaBrO3+z HClNaBr+H3AsO4+NaCl

where x,y,z are the stoichiometric coefficients of Na2HAsO3,NaBrO3,HCl respectively.
The value of x+y+z in the above balanced redox reaction is :

A
3
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B
9
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C
10
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D
12
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Solution

The correct option is C 10
The equation before balancing is:
Na2HAsO3+NaBrO3+HClNaBr+H3AsO4+NaCl

Oxidation state As in Na2HAsO3=+3
Oxidation state As in H3AsO4=+5
Oxidation state Br in NaBrO3=+5
Oxidation state Br in NaBr=1

Na2HAsO3 is undergoing oxidation and is the reducing agent
NaBrO3 is undergoing reduction and is the oxidising agent..


nf of Na2HAsO3=2
nf of NaBrO3=6

here 2 is common in both n-factors.

Ratio of n-factors=1:3

Cross multiplying these with ratio of nf's of each other.
we get,
3Na2HAsO3+NaBrO3+HClNaBr+H3AsO4+NaCl

Balancing As,
3Na2HAsO3+NaBrO3+HClNaBr+3H3AsO4+NaCl

As of now oxygen already got balanced,

Balancing Na,
3Na2HAsO3+NaBrO3+6HClNaBr+3H3AsO4+6NaCl

After this when we observe every element is balanced. so no need to follow further steps.
We can also see that charge on both sides is 0. which also indicates that the equation is balanced now.


3Na2HAsO3+NaBrO3+6HClNaBr+3H3AsO4+6NaCl

This is the final balanced equation.

Comparing to the equation given in question, we get,
The value of x,y,z to be 3,1,6 respectively.
Value of x+y+z=3+1+6=10

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