You visited us 3 times! Enjoying our articles? Unlock Full Access!

Heat

Consider a re...

Question

Consider a refrigerator and a heat pump working on the reversed Carnot cycle between the same temperature limits. Which of the following is correct?

COP of refrigerator = COP of heat pump

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

COP of refrigerator = Inverse of the COP of heat pump

No worries! We‘ve got your back. Try BYJU‘S free classes today!

COP of refrigerator = COP of heat pump

+ 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

COP of refrigerator = COP of heat pump

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A COP of refrigerator = COP of heat pump $- 1$
Refrigerator:
Coefficient of performance of refrigerator,
$(C O P)_{R} = \frac{C o o l i n g e f f e c t : Q_{2}}{W o r k i n p u t : W}$
$\frac{Q_{2}}{W}$

Heat pump:
Coefficient of performance of heat pump,
$(C O P)_{H P} = \frac{H e a t i n g e f f e c t : Q_{1}}{W o r k i n p u t : W} = \frac{Q_{1}}{W}$
$(C O P)_{H P} = \frac{Q_{1} - Q_{2} + Q_{2}}{W}$
$(C O P)_{H P} = \frac{W + Q_{2}}{W}$ $∵$ $W = Q_{1} - Q_{2}$
$(C O P)_{H P} = 1 + \frac{Q_{2}}{W}$
$(C O P)_{H P} = 1 + (C O P)_{R}$
or $(C O P)_{R} = (C O P)_{H P} - 1$

Suggest Corrections

Similar questions

27^{\circ} C a n d - 3^{\circ} C

- 5^{\circ} C

35^{\circ} C

30^{o} C

- 10^{C}

750 W

1000 W

A

- 10^{\circ} C

27^{\circ} C

B

- 27^{\circ} C

17^{\circ} C

200 J

(β)

Join BYJU'S Learning Program