wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider a regular cube with positive point charge +Q in all corners except for one which has a negative point charge −Q. Let the distance from any corner to the center of the cube be r. What is the magnitude of electric field at point P, the center of the cube?


A
E=7kQr2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
E=1kQr2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
E=2kQr2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
E=6kQr2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C E=2kQr2
Due to symmetry, electric field due to pairs of charges at opposite corners will cancel each other except the opposite charges +Q and Q
Hence, resultant field strength at P is equal to
E=2×14πϵ0Qr2=2kQr2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon