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Consider a re...
Question
Consider a relation R(A,B,C,D,E,F) with functional dependencies
F =(
A
→
B
C
B
→
E
D
→
A
F
F
→
C
B
→
A
D
)
The number of super keys present in the relation are ________
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Solution
(a)
A
+
=
{
A
B
C
D
E
F
}
B
+
=
{
A
B
C
D
E
F
}
D
+
=
{
A
B
C
D
E
F
}
Clearly, there are three candidate keys,
T
h
u
s
,
N
(
A
∪
B
∪
D
)
=
N
(
A
)
+
N
(
B
)
+
N
(
D
)
−
{
N
(
A
∩
B
∩
D
)
w
h
e
r
e
,
N
(
A
∩
B
∩
D
)
represnts number of super
⇒
N
(
A
∪
B
∪
D
)
=
3
×
2
5
−
3
×
2
4
+
2
3
=
96
−
48
+
8
=
56
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0
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