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Question

Consider a relation R(A, B, C,D,E) with the following dependencies:Maximum possible superkeys on relation R is_______.F =(ABC,CAE,BD,CB)
  1. 24

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Solution

The correct option is A 24
R(A, B, C, D, E) Closure of (A*) = (A, B, C, D, E} Closure of (C*) = (A, B,C D, E}A and C are candidate keys of RTotal number of possible superkeys with A=A and any combination of B, C, D, E=24Similarly with C = 24Total number of superkeys = 24+2423 =16+168=24

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