Consider a sequence where the nth term- t n - n - q 22- n -1-2 - The value of t 3- t 4- t 5- t 53 equalsA- 1-5 Z-B- z-4 17C- 1-1485D- 1-20702-T2E- 2-495

The correct option is E 2/495Option (A) is the correct answer. Check the video for the approach. ...

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Consider a se...

Question

Consider a sequence where the nth term,
$t_{n} = \frac{n}{n + 2}, n = 1, 2.....$ The value of $t_{3} \times t_{4} \times t_{5} \times . . . . \times t_{53}$ equals

\frac{2}{495}

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\frac{2}{477}

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\frac{12}{55}

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\frac{1}{1485}

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\frac{1}{2970}

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Similar questions

n^{t h}

t_{n} = \frac{n}{(n + 2)},

t_{3} \times t_{4} \times t_{5} \times . . . \times t_{53}

S_{n} & n^{t h}

t_{n}

S_{n} = n^{3} + 2^{n + 1} \forall n \in N

(t_{5} - t_{3})

T_{1}, T_{2}, T_{3}, \dots

S_{1} = T_{1} + T_{2} + T_{3} + \dots + T_{n}

S_{2} = T_{2} + T_{4} + T_{6} + \dots + T_{n - 1}

n

\frac{S_{1}}{S_{2}}

T_{1} = T_{2} = 1

T_{1}, T_{2}, T_{3}, . . ., T_{n}

T_{n + 2} = (T_{n + 1})^{- 1} + T_{n}

n = 1, 2, 3

T_{2019}

S_{1} = T_{1} + T_{2} + T_{3} + . . . + T_{n}

S_{2} = T_{2} + T_{4} + T_{6} + . . . + T_{n - 1}

S_{1} / S_{2}

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